121x^2+33x+2=0

Solution for 121x^2+33x+2=0 equation:

121x^2+33x+2=0

a = 121; b = 33; c = +2;
Δ = b2-4ac
Δ = 332-4·121·2
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-11}{2*121}=\frac{-44}{242}
=-2/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+11}{2*121}=\frac{-22}{242}
=-1/11
$